尝试针对魅族20系设计新的计算逻辑
This commit is contained in:
@@ -0,0 +1,41 @@
|
||||
/// 容量提取工具
|
||||
/// 支持两种日志格式:
|
||||
/// 1. learned_cap(21 系列):单位 µAh,除以 1000 得到 mAh
|
||||
/// 2. remaining_cap(20 系列):单位 mAh,直接使用(但 21 系列的 remaining_cap 也是 µAh,需判断)
|
||||
class CapacityExtractor {
|
||||
static int? extractCapacity(List<String> lines) {
|
||||
final validLines = lines.where((line) => line.contains('tbat=')).toList();
|
||||
if (validLines.isEmpty) return null;
|
||||
|
||||
// 模式一:learned_cap(21 系列)
|
||||
final learnedReg = RegExp(r'learned_cap=(\d+)');
|
||||
for (String line in validLines.reversed) {
|
||||
final match = learnedReg.firstMatch(line);
|
||||
if (match != null) {
|
||||
return int.parse(match.group(1)!) ~/ 1000;
|
||||
}
|
||||
}
|
||||
|
||||
// 模式二:remaining_cap 最大值
|
||||
final remainingReg = RegExp(r'remaining_cap=(\d+)');
|
||||
int? maxRemaining;
|
||||
for (String line in validLines) {
|
||||
final match = remainingReg.firstMatch(line);
|
||||
if (match != null) {
|
||||
final value = int.parse(match.group(1)!);
|
||||
if (maxRemaining == null || value > maxRemaining) {
|
||||
maxRemaining = value;
|
||||
}
|
||||
}
|
||||
}
|
||||
if (maxRemaining == null) return null;
|
||||
|
||||
// 🟢 判断单位:如果数值大于 100000(约 100 mAh),则认为是 µAh,需除以 1000
|
||||
// 否则认为是 mAh,直接使用
|
||||
if (maxRemaining > 100000) {
|
||||
return maxRemaining ~/ 1000;
|
||||
} else {
|
||||
return maxRemaining;
|
||||
}
|
||||
}
|
||||
}
|
||||
Reference in New Issue
Block a user